black holes and e=mc^2

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romat
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black holes and e=mc^2

Post #1

Post by romat »

e=mc^2
where e is energy m is mass and c is the speed of light.
now c = c+v (where v=velocity/speed of the observer)
So basically this makes it imposible to travel at the speed of light.
However light travels at the speed of light and a black hole can stop light meaning it must have some sort of mass.
So light must have infinite energy yet solar panels prove that it doesn't.
Can anyone explain?

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Post #2

Post by McCulloch »

Why don't you ask an astrophysicist from NASA? This post has nothing to do with Science and Religion, just science, so I am moving it to Random Ramblings.

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Re: black holes and e=mc^2

Post #3

Post by Furrowed Brow »

romat wrote:e=mc^2
where e is energy m is mass and c is the speed of light.
now c = c+v (where v=velocity/speed of the observer)
So basically this makes it imposible to travel at the speed of light.
However light travels at the speed of light and a black hole can stop light meaning it must have some sort of mass.
So light must have infinite energy yet solar panels prove that it doesn't.
Can anyone explain?
c = c + v does not look right to me.

The reason we cannot travel faster than c is down to the equation M/(1-(v^2/c^2))^1/2. where v is the velocity of the mass M. This equation guarantees that the faster you go, there will be an increase in your relative mass. As your speed approaches C your relative mass approaches infinity. Thus it takes an infinite amount of energy to achieve C.
However light travels at the speed of light and a black hole can stop light meaning it must have some sort of mass.
Why do you draw that conclusion? Light follows the shortest path. Black holes curve space, so the shortest path remains within the horizon of the black hole.

romat
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Post #4

Post by romat »

The reason we cannot travel faster than c is down to the equation M/(1-(v^2/c^2))^1/2. where v is the velocity of the mass M. This equation guarantees that the faster you go, there will be an increase in your relative mass. As your speed approaches C your relative mass approaches infinity. Thus it takes an infinite amount of energy to achieve C
If my thinking is right (which it usually isn't) light always travels at a constant speed (according to einstein).
einstein said:
even if we were chasing a beam of light whilst riding a beam of light the beam of light we were observing would still race away
or something like that i cant remeber the exact words.
the point is by constant it means that no matter what point of veiw you are looking at light from it is always traveling at light speed faster than the observer.
Why do you draw that conclusion? Light follows the shortest path. Black holes curve space, so the shortest path remains within the horizon of the black hole.
Gravity can only stop things with a mass (a.k.a a blackhole does not suck in space it has no mass).
I never liked the idea that gravity could warp space (doesnt stop it from being more than likely true the proof is undeniable) but light would escape the curve if it had no mass like a bullet going at the speed of 7mp/s could never be stopped by earths gravity.

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Post #5

Post by Openmind »

c = c + v does not look right to me.
Nor me. In fact it is very wrong. C is constant as you point out romat. It does not change, regardless of the observer and regardless of referential frame. Light by no means has infinite energy. The energy of light is quantised into "packets" of energy known as photons (you've probably heard of them).

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