Sorry but do you have
any data to back up that speculation? I mean, the under-crust water chambers aren't just unfounded they are actually impossible.
If they were below the crust (which would be required for them to account for continental drift the water would have mixed with the mantle. Doesn't make any sense.
The "pre-flood" condition must have had NO deviation in surface elevation as I shall prove:
The 4th order differential equation of elastic sheet load is
d4z
D ---- + (pm-pw)zg = P(x)
dx4
where P(x) is the load as a function of horizontal distance, z is the displacement of the load, g is the acceleration of gravity, pm is the density of the crust, pw is the density of water, D= ET3 /(12(1-sig2 ) where E is Young's modulus, 1011 dynes/cm2, sig is Poison's ratio, .25, and T is the thickness of the crustal layer into which the load sinks. For a two dimensional load with a 1/2 width, A, the flexure of the crust is
z max= h(ps-pw)(1-e-LA cos(LA))/(pm-ps)
where L= 4th root((pm-pw) g)/(4D))
With a crust thickness of 5 km (5x105 cm) sig= .25, E= 1011 we have
D = 1.1 x 1028
L = 4.37 x 10-7
Now for a mountain 10 km (1 x 106 cm) in radius and 5 km (5 x 105 cm) in height (h), the minimum thickness of the crust must be 5 x 105 (2.1-1) (1-e-LA cos(LA))/(2.65-2.1) = 1.1 x 106 cm =
4.1 km. The bending of the crust by 4.1 km will occur by
fracture as the crust is not flexible enough. This would immediately release the water. Thus, there are no mountains. Even a hill 1 km high would require that the crust bend by 830 metres.
This contradicts the biblical account as it says even the high mountains are covered.
What would the pressure of the water be?
Suppose you placed the water under only 10 km of crust (the crust is 50km thick in reality), the pressure of the water would be 10 x 105 * 980 * 2.65 = 2.58 x 10^9 dynes=
2562 atmospheres of pressure. The temperature gradient is 1 deg C for every 30 m so there is a 166 deg. C increase in temperature as we go deeper. 330 + 30 deg C (the surface temperature) =360 deg. C. For a layer of cave water 2 km thick all around the earth would contain 1 x 1024 cubic centimetres of water. At 360 deg C, the high temperature water would contain 3.3 x 1026 calories. (1 calorie per degree rise (330 degree rise)). The minute the pressure is released the water will turn to steam and you will cook the earth. Dividing the calories by the surface area of the earth shows that heat /cm2 = 3.3 x 1026 Calories/5.09 x 1018 square centimeters =
6.4 x 10^7 Cal/cm2.
That is the equivalent of 60 years worth of sun heating on one square cm
instantaneously. Everything would COOK not be flood - it is enough energy to raise water to 64,000,000 degrees (at 1Cal/degree).
A final note is made about this:
"On final item. I have seen the IPOD seismic line, from the continent out into the Atlantic mid oceanic ridge, every inch of it, and there is ABSOLUTELY NO EVIDENCE OF ANY RESIDUAL BURIED WATER OR DEEPLY BURIED CAVE TO HOLD THE WATER. There are no indications of collapse structures of the size your model would require anywhere on any seismic data I have ever examined in the past 25 years.
I would also point out that there is a type of seismic wave, called a shear wave which doesn't travel through water. In Brown's scenario, there would be no way to absolutely eliminate all the subterranean water. As the crust collapsed, rubble would block the escape route for some of the water. Given that shear waves don't travel through liquids, those of us in the seismology business should be able to find places where shear waves don't travel to the receivers. If the water is shallow, it would only block a few seismology stations.
But, we don't find any places in the shallow earth which won't transmit shear waves. That is very strong evidence that there is no residual water remaining under the crust."
http://home.entouch.net/dmd/hydroplate.htm
Consider the Hydroplate Flood Theory debunked.
A little closer to home is a piece about the Orkney Islands:
http://home.entouch.net/dmd/orkney.htm
